is there a way to return absolute path of a file and or folder by find?
let's say filename.txt in C:\test
set file=filename.txt dir %file% /s at now it return c:\test in line 6. but what i want is it return absolute path
c:\test\filename.txt and set it to variabel to be use next time.
thank you
Simply add the /B option to the dir/S command line, so it returns full absolute paths.
To capture the output of this command line, use a for /F loop:
for /F "delims=" %I in ('dir /S /B "filename.txt"') do rem/ Do something with `%I`... For example, to delete matching files, do this:
for /F "delims=" %I in ('dir /S /B "filename.txt"') do del "%I" Note that you have to double the % signs for this code to be used within a batch file, so %I becomes %%I!
:loop and goto loop how i can achieve this without hungry resource?for /F "delims=" %%I in ('dir /S /B %file&') do findstr,%file%,, "%%I" from above code i inialize filename to variabel file and using findstr to replace with 3 argument. 1. filename. 2. change to empty. 3. output from dir. to use later with rmdir. thx
\.. (like %I\.. in my code); to resolve it (so to change C:\test\boo\filename.txt\.. to C:\test\boo) use a standard for loop (no /F): for %J in ("C:\test\boo\filename.txt\..") do echo/%~J, or for %J in ("%I\..") do echo/%~J in my code...
dir /B without /S: for /F "delims=" %I in ('dir /B "filename.txt"') do set "FILE=%~fI"…Assuming that you get the filename as a first argument to a batch script, your batch-script could look like this:
set file=%~dpnx1 echo %file% Calling the script will return the the absolute path to the given file and you may use it as a variable onwards. More details on this can be found in the post: Resolve absolute path from relative path and/or file name
%~f1? ;-)
dir /S /Breturns full paths...dir filename /s /b | deli dont know how to bypass the return to del.