parametrized jenkinsFile : file parameter

Question

I want to configure a parametrized job in jenkins, who manipulate file:

 parameters([ file(defaultValue: 'DEFAULT', name : 'tomcatCodesUrl' , description: 'URL of service where to find tomcat mapping json file'),

the issus is , this parameter only return the name of the file. how can I acces to this content?

Vitalii Vitrenko · Accepted Answer · 2017-11-10 10:55:45Z

1

Currently there is no easy way to do this. You can find discussion about this in JENKINS-27413

answered Nov 10, 2017 at 10:55

Vitalii Vitrenko

10.6k5 gold badges48 silver badges69 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Kent Kostelac · Accepted Answer · 2019-07-29 05:23:08Z

Yeah that parameter is as redundant as it can be. Might aswell just use string.

Anyway. You can get the files content with readFile:

def content = readFile encoding: 'utf-8', file: 'tomcatCodesUrl'

Zheng Liu · Accepted Answer · 2019-12-18 07:04:44Z

How to use file parameter in jenkins

This post might be helpful. The upshot is, when users upload a file, it will be saved into the root directory of the project's workspace. You can directly access the file using any programming language you like, given the file name. The file content is not returned to you as a parameter, but anyway, since you know its saved place (workspace dir) and file name, you are in control.

Collectives™ on Stack Overflow

parametrized jenkinsFile : file parameter

3 Answers 3

Comments

1 Comment

Comments

Linked

Hot Network Questions

Collectives™ on Stack Overflow

3 Answers 3

Comments

1 Comment

Comments

Linked

Related