else executed with if inside of for

Question

I have a problem with 'if' executed together with 'else' when the value is equal to zero, the indentation seems fine so else is not part of for-else loop:

for i in range(0,5): if i == 0: print("i0 =", i) if i == 2: print("i2 =", i) else: print("else i=", i) i0 = 0 else i= 0 else i= 1 i2 = 2 else i= 3 else i= 4 >>>

You actually have 2 if blocks here. The first one which is alone (without any else) and the second one which does have an else clause. Both of them are ran in every iteration. — Ma0
– Ma0, Commented Feb 5, 2018 at 15:27

bipll · Accepted Answer · 2018-02-05 15:28:12Z

You don't have any problems. If you wanted those two ifs to form a single conditional branching, the second one should have been an elif. Right now, the loop body is comprised of two separate if statements and they are executed as: first, i is compared against zero; next again, i is compared against 2. So, when it is 0, the first if's then-block is triggered, and since it is not 2, the second if's else-block is triggered as well.

Did you actually mean

for i in range(0,5): if i == 0: print("i0 =", i) elif i == 2: print("i2 =", i) else: print("else i=", i)

?

ReturnTable · Accepted Answer · 2018-02-05 15:35:03Z

You're probably invalidating the first condition by the second "if" in the statement. I don't know python thus I'm not aware of any other conditional logic but it should be something like this:

for i in range(0,5): if (i == 0 or i == 2): print("if i =", i) else: print("else i=", i)

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