Let's say I have a Python script named script1.py that has the following code:
import sys name = sys.argv[1] print("Bye", name) And a second Python script script2.py that calls the first one:
import sys name = sys.argv[1] print("Hello", name) import script1 How can I pass an argument from the second script to the first one, as in the given examples?
I'd like the output to look like this when I run my script from the terminal:
>> python script2.py Bob Hello Bob Bye Bob A couple of options the way you're doing it (although your example does actually work right now because sys.argv is the same for both scripts but won't in the generic case where you want to pass generic arguments).
Use os.system
import os os.system('python script1.py {}'.format(name)) Use subprocess
import subprocess subprocess.Popen(['python', 'script1.py', name]) A better way, IMO, would be to make script 1's logic into a function
# script1.py import sys def bye(name): print("Bye", name) if __name__ == '__main__': # will only run when script1.py is run directly bye(sys.argv[1]) and then in script2.py do
# script2.py import sys import script1 name = sys.argv[1] print("Hello", name) script1.bye(name) 
main function or something and then use the if __name__ == '__main__': trick. If this worked, could you please accept the answer :)