$useridtofind= 123; $users=array(); while ($data = mysql_fetch_array ($result)) { $userid = $data['userid']; $age = $data['age']; $gender = $data['gender']; $dob = $data['dob']; $users[$userid] => array( 'age'=> $age, 'gender'=> $gender, 'dob' => $dob ) } $useridtofind=123; for($v=0; $v< count($users); $v++) { if($users[$v]== $useridtofind) { //how to go with grab value of age, gender, dob here? } } 
Add a comment |
2 Answers
You already use the id to index the array.
Just use:
if (isset($users[$usertofind])) { $user = $users[$usertofind]; echo $user['age']; echo $user['dob']; echo $user['gender']; } EDIT: Added isset check and reduced the number of times referencing the same array element
Comments
You seem to be using the user id as the index of the user in the array. If this is the case, you shouldn't be using a for loop, you should just check if the key exists within the array:
$useridtofind = 123; if (array_key_exists($useridtofind, $users)) { $user = $users[$useridtofind]; echo "User exists: ", $user['age'], '/', $user['gender'], '/', $user['dob']; } else { echo "User doesn't exist"; } 