Django and absolute url with slug

Question

my model is like:

class Modeloxy(models.Model): ... ... slug = models.slug() class mymodel(models.Model): marca = ... ... modelo = models.ForeignKey(Modeloxy) def get_absolute_url(self): return '/%s/%s/%s' % (self.marca,self.modelo__slug,self.pk)

So, i can't get the absolute url usin self.modelo__slug.... how i will do that?

thanks guys

On the side note: consider using the reverse function to decouple urls from models docs.djangoproject.com/en/1.2/topics/http/urls/… — alex vasi
– alex vasi, Commented Feb 20, 2011 at 22:59

Yuji 'Tomita' Tomita · Accepted Answer · 2011-02-20 22:40:51Z

It would be self.modelo.slug

The double underscore syntax was created to solve the problem of not being able to use dot syntax as a keyword argument function(keyword_arg=Foo) and unrelated to python: you're literally looking for a variable named modelo__slug in your case.

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