How to remove unwanted '\n' from output

The simplest fix may be to just change the for-loop variable:

file_4 = open('numbers.txt','r') number_lines = 0 lines = file_4.readlines()[1:] for line in lines: # do not reuse previous variable here number_lines += 1 print(line.rstrip()) # strip the newline print(number_lines) 

seems to give your expected output:

2 3 4 5 4 

open the file. f.readlines() returns each line in the text file in a list.

Since a list is indexed from 0. list[1:] will skip the first one and give the rest.

with open("stack.txt") as f: txt_list = f.readlines() #That's a list for item in txt_list[1:]: #skip the first one print(item) 

output:

2 3 4 5 >>> 

And the \n is nothing but a special character denoting a new line. From your input you read multiple lines each having a new line character at the end. Also print prints each one in a new line. That's the reason for (Two newlines) gap between two numbers in above output.

You can join the list and print like this. Since each already has a new line character in it. What you are doing is printing the entire list in your code. yours:

output: ['2\n', '3\n', '4\n', '5'] 

Try this:

with open("stack.txt") as f: txt_list = f.readlines() out = ''.join(txt_list[1:]) print(out) 

output:

2 3 4 5 

Using .read().splitlines():

file_4 = open('numbers.txt','r') lines = file_4.read().splitlines()[1:] # .read().splitlines() will trim the newline chars number_lines = len(lines) # We don't need a loop to count the number of lines # We can use the `len` function. print(lines) print(number_lines) 

But this leaves file_4 open, and you're reading the entire file into memory unnecessarily.

Here, using a context manager, looping over the file's lines, and using .rstrip() to trim the newline characters:

with open('numbers.txt','r') as file_4: lines = [line.rstrip() for (i,line) in enumerate(file_4) if i > 0] number_lines = len(lines) print(lines) print(number_lines) 

A file is an iterator, which means you can use things like next and enumerate directly on the file, instead of reading the entire thing into memory at once. Use strip to remove the trailing newline. (strip actually removes all leading and trailing whitespace; line.lstrip('\n') would remove specifically trailing newlines.)

with open('numbers.txt', 'r') as file_4: next(file) # skip the first line for count, line in enumerate(file_4, start=1): print(line.strip()) print("Length:", count) 

enumerate basically numbers the lines (here, starting at 1), with count being the current line number. After this loop exits, count is still the number of the last line, which is also the total number of lines.

Use the following code:-

file_4 = open('numbers.txt','r') number_lines = 0 lines = file_4.readlines()[1:] # here we used map() to apply strip() function on each list item to remove \n lines = map(str.strip, lines) for file_4 in lines: number_lines += 1 # here we use join() with \n to print list item with new line. print('\n'.join(lines)) print(number_lines) 

output:-

2 3 4 5 4