exception handling mistake

Question

So I have a condition for accepting only a negative value for a variable and it should also not raise a value error. My code goes like this ->

try: x = int(input("Enter -ve value : ")) while x >= 0: print("Error wrong value!") x = int(input("Enter -ve value : " ) except ValueError: print("Error wrong value!") x = int(input("Enter -ve value : ")) while x >= 0: print("Error wrong value!") x=int(input("Enter -ve value : " )

The only problem with this approach is that, suppose I press enter without entering a value for the first time. It takes me to the "except" condition and it works fine but if I enter a blank value again my code stops because of value error. How do I stop this from happening? Is there a more efficient way of writing this code without importing any modules?

Thank you for your time and efforts! I wrote this question on the mobile app so sorry if it causes any inconvenience!

@Isma I am sorry but I am quite new so if you could demonstrate that it would be awesome! — outcast_dreamer
– outcast_dreamer, Commented Jul 5, 2018 at 9:03
Your try..except splits the entire routine into two separate parts. You want one while with the try..except inside, not as an outer control loop. — Jongware
– Jongware, Commented Jul 5, 2018 at 9:11

AJC24 · Accepted Answer · 2018-07-05 09:07:52Z

You could try it like this:

x = 0 while x >= 0: try: x = int(input("Enter -ve value : ")) except ValueError: print("Error wrong value!") x = 0

This will achieve what you are asking for in that it will keep prompting you to enter a number while x >= 0 and will also ensure the exception handling is always carried out on each input too.

Collectives™ on Stack Overflow

exception handling mistake

1 Answer 1

Comments

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Related