If loop being ignored

Question

I wrote a Python programm that is ignoring the if loop. Could somebody please help me by telling me what I did wrong? Please see the code below:

class Check(): def __init__(self, op1, op2, op): self.op1 = op1 self.op2 = op2 self.op = op def main(): print("Enter first number: ") num1 = int(input()) print("Enter second number: ") num2 = int(input()) print("Enter operation: ") op=str(input()) if op == '+': return op1 + op2 elif op == '-': return op1 - op2 elif op == '*': return op1 * op2 elif op == '/': return op1 / op2 if __name__ == "__main__": main()

Well, first of all if is not a loop. Second, your code just defines a class but no instance or method are ever created/called — rafaelc
– rafaelc, Commented Aug 5, 2018 at 23:09
Where is your main driver? What's the input the user gives it? — ggorlen
– ggorlen, Commented Aug 5, 2018 at 23:09

user10030086 · Accepted Answer · 2018-08-05 23:22:15Z

The problem is there is nothing that is op1 and op2, there is self.op1, self.op2, num1, and num2. I am assuming you want to add num1 and num2. Also you didn't put

self

in cheese, here is the working program

class Check(): def __init__(self, op1, op2, op): self.op1 = op1 self.op2 = op2 self.op = op def cheese(self): print("Enter first number: ") op1 = int(input()) print("Enter second number: ") op2 = int(input()) print("Enter operation: ") op=str(input()) if op == '+': return op1 + op2 elif op == '-': return op1 - op2 elif op == '*': return op1 * op2 elif op == '/': return op1 / op2 a = Check(1,2,"+") print(a.cheese())

Hello the code was edited to include a main() function. I now get an error that main() is not defined.
Again you need to put self, as its part of a class, then you have to initialize Check with something like 'a = Check()' then because main is part of the Check class you would say 'a.main()' it might not make sense to you now, but i'm sure in a while you will understand it.

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