How to avoid case sensitivity in Python

Using lower to convert the tuple to lower case for comparison

list2= [('Tom','100'),('Alex','200')] list3= [('tom','100'),('alex','200')] non_match = [] for line in list2: name, val = line if (name.lower(), val) not in list3: non_match.append(line) print(non_match) 

You can't avoid transforming your data to some case-insensitive format, at some point. What you can do is to avoid recreating the full lists:

def make_canonical(line): name, number = line return (name.lower(), number) non_match = [] for line2 in list2: search = make_canonical(line2) for line3 in list3: canonical = make_canonical(line3) if search == canonical: break else: # Did not hit the break non_match.append(line3) 

You need to iterate tuples also inside loop

for line2 in list2: for line3 in list3: if len(line3) == len(line2): lenth = len(line3) successCount = 0 match = False for i in range(lenth): result = line2[i].lower() == line3[i].lower() if result == True: successCount = successCount +1; result = False if successCount == lenth: non_match.append(line2) print(non_match) 

enjoy.....

You can make the comparison even more generic mixing ints and whitespaces in the game by creating two dicts from your tuple-lists and compare the lists:

def unify(v): return str(v).lower().strip() list2= [('Tom ','100'),(' AleX',200)] list3= [('toM',100),('aLex ','200')] d2 = {unify(k):unify(v) for k,v in list2} # create a dict d3 = {unify(k):unify(v) for k,v in list3} # create another dict print(d2 == d3) # dicts compare (key,value) wise 

The applied methods will make strings from integers, strip whitespaces and then compare the dicts.

Output:

True