Is it possible in Node.js to detect if code executes some other script/file

Question

Imagine this code:

const myFunc = () => exec('node foo.js')

Now my library executes myFunc, but it doesn't know if it executes another script. How to make it know it?

P.S. The lib, which is a test runner + coverage tool, needs to know every piece of code that was run by the test.

Why does the lib need to 'know' this? This is none of its concern. A function is a function. — Estus Flask
– Estus Flask, Commented Nov 10, 2018 at 6:55
The lib, which is a test runner + coverage tool, needs to know every piece of code that was run by the test. This is a simplified description. — Nurbol Alpysbayev
– Nurbol Alpysbayev, Commented Nov 10, 2018 at 7:13
Consider updating the question with relevant details, so it would be clearer for users who may have the same problem. — Estus Flask
– Estus Flask, Commented Nov 10, 2018 at 7:21

Estus Flask · Accepted Answer · 2018-11-10 07:28:36Z

If there's a need to detect API calls that may result in uncontrolled script execution and there's a need to detect calls, APIs have to be patched, e.g.:

const childProcess = require('child_process'); const { exec } = childProcess; childProcess.exec = function () { console.error(new Error('No coverage')); return exec.apply(this, arguments); };

This applies to global.eval, global.Function, all child_process module functions, some vm and worker_threads functions.

Wow, I always over-engineer things, when indeed this (patching/decorating) can be done! Great idea, thanks! And listing possible patch-ables is very good!

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