How to get the calling method's name at runtime

Question

I have:

def outer_method() called_method() end def called_method() puts "name of outer_method" end

Is it possible for the called_method to get the name of the outer_method without assigning __method__ in the outer_method and then using it as an argument of called_method?

sawa · Accepted Answer · 2018-12-05 04:16:05Z

Yes. An old school way is to go like this:

def outer_method called_method end def called_method puts caller.first[/(?<=`).+(?=')/] end outer_method # >> outer_method

A more modern and robust way is to do:

def outer_method called_method end def called_method puts caller_locations.first.label end outer_method # >> outer_method

If you mean regex, or Regexp, then yes. It passes a regex to the method [].

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