Ignore TypeError in Python

Question

I am working on some soon-to-be obsolete scientific software written in Python (Enthought Python Distribution, Python 2.7.1, IPython 0.10.1). We need to check if the older results are correct, but with the massive amount of data we have the GUI procedure we need to make working with non-GUI mode. The important piece of code is to save the data:

def _save_button_fired(self): self.savedata()

In GUI when we click on the button the file is saved correctly. In non-GUI mode, when we do the following:

m.savedata()

the file is created, but a number of errors appear starting with:

--------------------------------------------------------------------------- TypeError Traceback (most recent call last)

etc. etc. When I use CTRL+D, select Y to kill the Python, the file is quite surprisingly written correctly. This is suffcient for our needs. However, is there any way to ignore the error and just proceed further with the code? I looked at the forum for solutions but non of them seems to fit my situation. Also, I am not keen on Python, thus would be grateful for a working solution. With many thanks.

Sounds like you’re seeing messages written to standard error while the file is being written. But it’s impossible to tell from this little information. — Davis Herring
– Davis Herring, Commented Mar 23, 2019 at 19:10

David Silveiro · Accepted Answer · 2019-03-23 19:19:50Z

4

You could wrap it in a try/pass :)

try: self.savedata() except TypeError: pass

edited Mar 23, 2019 at 19:19

answered Mar 23, 2019 at 19:10

David Silveiro

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5 Comments

Davis Herring Over a year ago

Don’t use a bare except:; it catches too much.

sanyassh Over a year ago

Also the current syntax is invalid. Edit it please to lowercase try, except, pass.

Edgecase Over a year ago

Try using except TypeError: instead. It will single out that error only :)

David Silveiro Over a year ago

Updated to reflect the above :)

rk85 Over a year ago

Thanks a lot! Works like a charm:) Later I just kill it completely with pid = os.getpid() os.kill(pid, 9) and this clumsy solution is enough for me:)

Luke Singham · Accepted Answer · 2023-01-17 09:12:01Z

An alternative to the try/pass solution is contextlib.suppress.

with contextlib.suppress(TypeError): self.savedata()

Why one over the other?

The context manager slightly shortens the code and significantly clarifies the author's intention to ignore the specific errors. The standard library feature was introduced following a discussion, where the consensus was that: A key benefit here is in the priming effect for readers... The with statement form makes it clear before you start reading the code that certain exceptions won't propagate.

Source: sourcery.ai

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