All the time I tried to compare two variables with type None but it doesn't work.
example:
if type(a and b) == type(None): #do something else: #do other stuff Does somebody know the right statement and an explanation?
3 Answers
You can check differently.
if a is None and b is None: print('Both a and b are None') else: print('a and b are not None') Issues with your code.
a and bwill return eitheraorb- type comparison is not a good option.
1 Comment
bereal
To be precise,
a and b will return either a or b.In Python, if you want to check for null variables, you should use the x is None syntax. There is only one instance of the None object in a Python runtime (it's called a singleton). Moreover, checking against type tends to be bad practice in general. In your case, you should do:
if a is None and b is None: #do something else: #do other stuff You can also simplify it to if (a and b) is None, since the and operator will propagate the None if one of a and b is None.
Comments
def nonetype_check1(a,b): if a==b and a==None: print(" both are nonetype type",type(a)) elif a!=b: print("values of both are not same",a,b) else: print("values of both are same but not nonetype",type(b),type(b)) output: 1)a=Nonetype,b=Nonetype,answer:both are nonetype type 2)a=Nonetype,b=3, answer:values of both are not same None 3 3)a=3,b=3, answer:values of both are same but not nonetype
if a is None and b is None...