I have a simple question. I have two arrays A and B, I want to retain A objects if B has the same ID. For example:
const A = [{id: "price", value: "1"}] const B = [{id: "price", value: "0"}, {id: "number", value: "0"}] Expected result:
[{id: "price", value: "1"}, {id: "number", value: "0"}}] How can I do this?
I tried to map A and foreach B inside A but it didn't work.
const result = A.concat(B.filter(bo => A.every(ao => ao.id != bo.id))); Concatenate all the objects from A with objects from B that aren't in A (which is done by filtering only objects from B where there isn't an object in A with the same id).
Example:
const A = [{id: "price", value: "1"}]; const B = [{id: "price", value: "0"}, {id: "number", value: "0"}]; const result = A.concat(B.filter(bo => A.every(ao => ao.id != bo.id))); console.log(result);You'd use reduce on the merged array - also turn the value into a number:
const A = [{id: "price", value: "1"}]; const B = [{id: "price", value: "0"}, {id: "number", value: "0"}]; const res = Object.values([...A, ...B].reduce((acc, { id, value }) => { if (acc[id]) acc[id].value += parseInt(value); else acc[id] = { id, value: parseInt(value) }; return acc; }, {})); console.log(res);.as-console-wrapper { max-height: 100% !important; top: auto; }
Another option that you could try (I believe it would be O(n) ) is to convert arrays to objects with id as key then extend (jquery.extend or pure js implementation) then convert the merged object back to array.
const A = [{id: "price", value: "1"}]; const B = [{id: "price", value: "0"}, {id: "number", value: "0"}]; //convert arrays to objects var Bx = {}; B.forEach(i => Bx[i.id] = i); var Ax = {}; A.forEach(i => Ax[i.id] = i); //copy all matching id properties from A to B A.forEach(i => Bx[i.id] = Ax[i.id]); //convert the merged object to array var C = []; Object.getOwnPropertyNames(Bx).forEach(i => C.push(Bx[i])); console.log(C);
A's objects orB's objects? The expected result is confusing