I have a function called testin namespace buzz.
From this test function i am calling another function called dummy which is inside namespace example.
I get the following error:
Dummy is not a member of example.
Can you please tell me how to communicate between 2 different namespaces?
Thanks
Following code works with gcc (as expected). Your problem must be with something that is not in the question.
#include <iostream> namespace example { void dummy() { std::cout << "Dummy\n"; } } namespace buzz { void test() { example::dummy(); } } int main() { buzz::test(); } If the namespace is not nested, you should start navigating from the root one, i.e.:
Instead of:
example::dummy Write:
::example::dummy 
namespace myns {/*my code*/}, and I am perfectly able to call 3rd party functions from their namespaces, starting with std. I think we should look at the codeYou need to provide code for this query. Otherwise just from your question, I guess you are making spelling error:
namespace example { void dummy() {} } namespace buzz { void test () { example::Dummy(); } // capital 'D' instead of 'd' for dummy } Naturally, Dummy is not a member of example. :))
