I'm doing a little project and I essentially need to figure out the middle 5 digits of a number (e.g. 123454321 would return 34543). If the number is 4 digits (e.g. 1234) it will return the middle two (in the case of 1234 this would be 23). If the number is 3 digits, it will return the middle number (e.g. 123 would return 2), and if the number is 1 or 2 digits the code won't accept the input.
I've tried doing some research about this online, but haven't really managed to find anything other than the "Middle-square method" but the implementation for python they have doesn't seem to work.
num = 730945296 #Random number for testing num_len = len(str(num)) print(num*num) #debug print(str(num*num).zfill(num_len)) #debug num = int(str(num*num).zfill(num_len)[round(num_len/4):round((num_len/4)*3)]) print(num) is my representation of the implementation for python but as I stated above, this doesn't seem to work.
In this case the output was 9452 but I expected 09452.
I'm aware I'm not doing extra checks like whether output is more than 5 digits or how long input is but I figured I should concentrate on getting the middle digits first.
