Unable to Zip a File in Buffer

Question

i Want to Zip the CSV File in (Buffer) Using zipFile in Python

Below is My Code Which I Have Tried And Error Log Attached

I Dont want to use the compression in df.to_csv due to Version issue

import pandas as pd import numpy as np import io import zipfile df = pd.DataFrame(np.random.randn(100, 4), columns=list('ABCD')) s_buf = io.StringIO() df.to_csv(s_buf,index=False) s_buf.seek(0) s_buf.name = 'my_filename.csv' localfile= io.BytesIO() localzip = io.BytesIO() zf = zipfile.ZipFile(localzip, mode="w",compression=zipfile.ZIP_DEFLATED) zf.writestr(localfile, s_buf.read()) zf.close() with open("D:/my_zip.zip", "wb") as f: f.write(zf.getvalue())

Error I am Getting

Traceback (most recent call last): File "C:/Users/Window/PycharmProjects/dfZip/dfZiptest.py", line 25, in <module> zf.writestr(localfile, s_buf.read()) File "C:\Python\Python37\lib\zipfile.py", line 1758, in writestr date_time=time.localtime(time.time())[:6]) File "C:\Python\Python37\lib\zipfile.py", line 345, in __init__ null_byte = filename.find(chr(0)) AttributeError: '_io.BytesIO' object has no attribute 'find'

Kea Ivo · Accepted Answer · 2019-06-03 05:50:33Z

zf = zipFile.ZipFile("localzip.zip", mode="w", compression=zipfile.ZIP_DEFLATED) zf.write(filename + '.cvs', s_buf.read()) zf.close

What you are doing here is

1 - You initializa the path of the ZipFile

2 - You simply pass the name and then the file you want to be written to the archive. In your case you were passing io.BytesIO() as a name, which made no sense to Python, thus the error.

I would strongly advice you, to resolve any Version issues first, because while 'clever' solution may seem like a quick way out, they tend to rack up a terrible technical debt latter, which can and will be a nightmare to deal with.

this Line wont Work as the FIle in Buffer if Use This gives Error FileNotFoundError: [WinError 2] The system cannot find the file specified: 'my_filename.cvs'

pypypy · Accepted Answer · 2019-06-03 04:23:08Z

0

You are passing a io.BytesIO() object as the first argument to ZipFile.writestr() where it expects either an archive name or a ZipInfo object.

zf.writestr(localfile, s_buf.read())

zinfo_or_arcname is either the file name it will be given in the archive, or a ZipInfo instance.

source: Docs

answered Jun 3, 2019 at 4:23

pypypy

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4 Comments

Panda Over a year ago

I Tried Doing that Change By Giving a File Name Now its Giving Error While Writing the Zip File

pypypy Over a year ago

You'd need to post the error for me to provide further assistance.

Panda Over a year ago

Traceback (most recent call last): File "C:/Users/sagar/PycharmProjects/dfZip/dfZiptest.py", line 16, in <module> f.write(zf.getvalue()) AttributeError: 'ZipFile' object has no attribute 'getvalue'

pypypy Over a year ago

The error is pretty obvious - ZipFile instances do not have a getvalue method. I think you need to review the documentation.

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