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i have a table like so: 

email | segment | exit --------------------------------------------- [email protected] | abandoned_cart | true [email protected] | purchased_last_7_days | false [email protected] | abandoned_cart | true [email protected] | purchased_last_7_days | false [email protected] | abandoned_cart | true

I am trying write a query to get a count of unique email addresses that have BOTH abandoned_cart = true and purchase_last_7_days = false

This is what I tried but recieved 0: 

SELECT COUNT(DISTINCT email) FROM `table_seg_changes` WHERE (segment_slug = 'purchased_last_7_days' AND exit = false) AND (segment_slug = 'abandoned_cart' AND exit = true)
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Below is for BigQuery Standard SQL 

#standardSQL SELECT email FROM `project.dataset.table` GROUP BY email HAVING COUNTIF( (segment = 'abandoned_cart' AND exit) OR (segment = 'purchased_last_7_days' AND NOT exit) ) = 2

You can test, play with above using sample data from your question as in below example 

#standardSQL WITH `project.dataset.table` AS ( SELECT '[email protected]' email, 'abandoned_cart' segment, TRUE exit UNION ALL SELECT '[email protected]', 'purchased_last_7_days', FALSE UNION ALL SELECT '[email protected]', 'abandoned_cart', TRUE UNION ALL SELECT '[email protected]', 'purchased_last_7_days', FALSE UNION ALL SELECT '[email protected]', 'abandoned_cart', TRUE ) SELECT email FROM `project.dataset.table` GROUP BY email HAVING COUNTIF( (segment = 'abandoned_cart' AND exit) OR (segment = 'purchased_last_7_days' AND NOT exit) ) = 2

with result 

Row email 1 [email protected] 2 [email protected]

Note: above assumes there is no duplicate entries for segments/exit values for the same email (as it is looks like from your example)

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