Unable to apply parameterised curried function

Question

I have a function, that has the following definition:

def expectMsgPF[T](max: Duration = Duration.Undefined, hint: String = "")(f: PartialFunction[Any, T]): T = {

When I call it as follows:

val res1 = listener1.expectMsgPF(1.second)

Is res1 a function?

I would like to write as follow:

 val res1 = listener1.expectMsgPF(1.second) _ val res2 = listener2.expectMsgPF(1.second) Then("it should contain `Kafka and SAP are offline`") res1 { case status: ServerStatus => status.health should be(ServersOffline) }

But it does not work.

expectMsgPF is a method, not a function. - res1 can be a function, if the expected type is of a function. — Luis Miguel Mejía Suárez
– Luis Miguel Mejía Suárez, Commented Jun 9, 2019 at 19:42

Mario Galic · Accepted Answer · 2019-06-09 20:05:51Z

To make res1 { case status: ServerStatus => status.health should be(ServersOffline) } work, try helping the compiler out by providing type parameter T to expectMsgPF[T] like so

val res1 = listener1.expectMsgPF[Assertion](1.second) _

This makes res1 indeed a function of the type

PartialFunction[Any, Assertion] => Assertion

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