How do I split individual strings in a list?
data = ('Esperanza Ice Cream', 'Gregory Johnson', 'Brandies bar and grill') Return:
print(data) ('Esperanza', 'Ice', 'Cream', 'Gregory', 'Johnson', 'Brandies', 'bar', 'and', 'grill') 
- 1and your attempts are?Avinash Raj– Avinash Raj2019-08-08 02:18:00 +00:00Commented Aug 8, 2019 at 2:18
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3 Answers
One approach, using join and split:
items = ' '.join(data) terms = items.split(' ') print(terms) ['Esperanza', 'Ice', 'Cream', 'Gregory', 'Johnson', 'Brandies', 'bar', 'and', 'grill'] The idea here is to generate a single string containing all space-separated terms. Then, all we need is a single call to the non regex version of split to get the output.
2 Comments
Todd Burus
I like this approach. Do you foresee any problems coming from it, i.e. it solves the problem as stated, but maybe doesn't generalize as well as some other approach?
Tim Biegeleisen
@ToddBurus It might not be the most space efficient method, because it generates a big ugly string.
data = ('Esperanza Ice Cream', 'Gregory Johnson', 'Brandies bar and grill') data = [i.split(' ') for i in data] data=sum(data, []) print(tuple(data)) #('Esperanza', 'Ice', 'Cream', 'Gregory', 'Johnson', 'Brandies', 'bar', 'and', 'grill') answered Aug 8, 2019 at 2:19
ComplicatedPhenomenon
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You can use itertools.chain for that like:
Code:
it.chain.from_iterable(i.split() for i in data) Test Code:
import itertools as it data = ('Esperanza Ice Cream', 'Gregory Johnson', 'Brandies bar and grill') print(list(it.chain.from_iterable(i.split() for i in data))) Results:
['Esperanza', 'Ice', 'Cream', 'Gregory', 'Johnson', 'Brandies', 'bar', 'and', 'grill'] 