How to print a row/column/diagonal from matrix

Question

I am trying to get my program print out the rows, columns or diagonals if they don't equal the magic square rule, for example, if the matrix is

1 9 5

2 4 3

6 8 7

Row 1 [2, 4, 3] doesn't work

Row 2 [6, 8, 7] doesn't work

Column 0 [1, 2, 6] doesn't work

Diagonal 1 [1, 4, 7] doesn't work

I've tried print("%d", matrix[row])

#include <stdio.h> #include <stdbool.h> #include <unistd.h> int main() { //declared variables int size = 3; int matrix[3][3]; int row, column = 0; int sum0, sum1, sum2; int flag = 0; //ask user to input 1-9 and scans it printf("Enter in the values: \n"); for (row = 0; row < size; row++){ for (column = 0; column < size; column++) scanf("%d", &matrix[row][column]); } //enters number into magic square format printf("You entered: \n"); for (row = 0; row < size; row++) { printf("\n"); for (column = 0; column < size; column++) { printf("%d ", matrix[row][column]); } } //diagonal calculations sum0 = 0; for (row = 0; row < size; row++) { for (column = 0; column < size; column++) { if (row == column) sum0 = sum0 + matrix[row][column]; } } //row calculations for (row = 0; row < size; row++) { sum1 = 0; for (column = 0; column < size; column++) { sum1 = sum1 + matrix[row][column]; } if (sum0 == sum1) flag = 1; else { flag = 0; break; } } //column calculations for (row = 0; row < size; row++) { sum1 = 0; for (column = 0; column < size; column++) { sum2 = sum2 + matrix[row][column]; } if (sum1 == sum2) flag = 1; else { flag = 0; break; } } printf("\nAnalyzing...\n"); if (flag == 1) { sleep(2); printf("This is a magic square!\n"); } else { sleep(2); printf("This is not a magic square!\n"); } return 0; }

Does your code not work as you expected? If so, then I suggest you debug it. Do you know how to debug your code? — Abra
– Abra, Commented Sep 19, 2019 at 18:19

monsieur patate · Accepted Answer · 2019-09-19 16:39:36Z

1

You have to use loops to print each character separately. printf(3) offers no way to print an array of integers.

answered Sep 19, 2019 at 16:39

monsieur patate

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Comments

boby · Accepted Answer · 2019-09-19 17:01:39Z

it seems weired that initailzied sum1 in colum calculations

//column calculations for (row = 0; row < size; row++) { sum1 = 0; // <= sum2 = 0; maybe for (column = 0; column < size; column++) { sum2 = sum2 + matrix[row][column]; } if (sum1 == sum2) flag = 1; else { flag = 0; break; } }

and if row calcuations used loop as below

for(row = 0; row < size; row++){ for(column = 0; column < size; column++){ // access to matrix[row][column] } }

column calculations loop will be revised

for(column = 0; column < size; column++){ for(row = 0; row < size; row++){ // access to matrix[row][column] } }

plus, you can write the diagonal calculations simply

//diagonal calculations sum0 = 0; for (int diag = 0; diag < size; diag++) { sum0 += matrix[diag][diag]; }

Sergey Teryan · Accepted Answer · 2019-09-19 16:56:49Z

I think you get the logic:

 const int x = 5; const int y = 7; int matrix[x][y]; for (int j = 0; j < x; ++j) { for (int i = 0; i < y; ++i) { matrix[j][i] = j + i; printf("%3d ", matrix[j][i]); } putchar('\n'); } puts("\nPrint a column: "); for(int i = 0; i < x; i++) { printf("%3d ", matrix[i][0 /*constant*/]); } puts("\nPrint a row: "); for (int k = 0; k < 7; ++k) { printf("%3d ", matrix[0/*constant*/][k]); } puts("\nPrint a diagonal"); for (int l = 0, m = 0; l < x && m < y; ++l, ++m) { printf("%3d ", matrix[l][m]); }

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