How do I determine if an index is a list/array or not? [duplicate]

Question

I am essentially trying to work out if a specified index is a list or not. I have a list embedded into an index.

This is what I have so far

 if len(hashTable[hashed-1])>1: hashTable[hashed-1].append(inVal) else: tempTable = [hashTable[hashed-1], inVal] hashTable[hashed-1] = tempTable print(inVal,hashed) print(hashTable)

The output of the list is: (the 0's an 10 are irrelevant)

[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, [1, 3], 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 10]

The error is:

 if len(hashTable[hashed-1])>1: TypeError: object of type 'int' has no len()

hashTable[hashed-1] is an int, not a list, hence the error, try if isinstance(hashTable[hashed-1], list) and len(hashTable[hashed-1]) > 1 — Dani Mesejo
– Dani Mesejo, Commented Oct 3, 2019 at 0:30
Thank you, the if isinstance(hashTable[hashed-1], list) worked — Kewmolk
– Kewmolk, Commented Oct 3, 2019 at 0:36

Massifox · Accepted Answer · 2019-10-03 00:41:11Z

You must use isinstance, to check if your object is a list type, as follows:

isinstance(hashTable[hashed-1], list)

in your case:

if isinstance(hashTable[hashed-1], list) and len(hashTable[hashed-1]) > 1

Python uses lazy evaluation, to evaluate the condition in this if-statement. So len(hashTable[hashed-1]) will be called only when isinstance(hashTable[hashed-1], list) is True.

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