Read lines from text file and store it in array

Question

So i need to read all the lines from a text file(as an argument when i call the script) which contains numbers in this form(1 new line not 2):
num1:num2

num3:num4 etc

I use this command block:

while IFS= read line do IFS=':' read -r -a X <<< "$line" done < "$1"

to read the lines and numbers and store it into array X but the array goes only to position 0 and 1 and when it changes line it just write the new number(eg num3) where the old number was(eg num1 in pos 0)

Any solution to this?

Insert before your code array=() and before done insert array+=( "${X[@]}" ) to append array X to array array. — Cyrus
– Cyrus, Commented Oct 12, 2019 at 8:52

Cyrus · Accepted Answer · 2019-10-12 08:27:38Z

2

With bash. Replace all : with line break and use mapfile to fill array x.

mapfile -t x < <(tr ':' '\n' < file) declare -p x

Output:

 declare -a x='([0]="num1" [1]="num2" [2]="num3" [3]="num4")'

See: help mapfile

answered Oct 12, 2019 at 8:27

Cyrus

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2 Comments

George Over a year ago

And what if i want to store the first number in one array and the second in a different array Y in each line

Cyrus Over a year ago

I recommend that you ask a new question (no comment) about this.

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