How to assign QAbstractListModel to ListModel

Question

I have an application which contains ListModel. I have written C++ class derived from QAbstractListModel.

QML List model looks like

// SelectedStepsModel.qml import QtQuick 2.0 ListModel { ListElement{ step_name:"" step_icon:""

and, C++ class looks like

class ProductModel : public QAbstractListModel { Q_OBJECT Q_PROPERTY(QString product_name READ get_product_name) public: enum { StepNameRole = Qt::UserRole, StepIconRole, ...

In main,

... ProductModel* product_model = new ProductModel(); context->setContextProperty("product_model", QVariant::fromValue(product_model)); ...

In one of the files (where QML model gets filled by some functions in QML) I want to replace that logic with newly created model ( as model has all data ).

// some other file SelectedStepsModel { id: selected_model } selected_model = product_model

Note, here selected_model is ListModel and product_model is QAbstractListModel. But selected_model = product_model is failing.

Am I doing the right thing else what is the correct way of assigning QAbstractListModel to ListModel.

Thanks in advance.

It can't be done, why don't you set product_model directly in view?: View{model: product_model} — eyllanesc
– eyllanesc, Commented Nov 1, 2019 at 12:26

Kuba hasn't forgotten Monica · Accepted Answer · 2019-11-01 12:50:54Z

There's no such thing as "assigning" the models here: either you use the model instance that you declared in QML, or you use the model you provided. Choose one or the other.

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