$script.js nested dependencies

Question

Is there a way to make the following work with $script.js:

control.js

$script('accounts.js', function() { // fnA });

accounts.js

$script('util.js', function() { // fnB });

I would have hoped that fnB is executed before fnA, but it's not. Therefore, namespaces and objects created in fnB are not available to fnA, namely the accounts functionality.

util.js contains only a namespace function.

Edgar Villegas Alvarado · Accepted Answer · 2011-05-04 05:23:51Z

2

You should do this:

control.js $script('util.js', function() { // fnB $script('accounts.js', function() { // fnA }); });

And it wouldn't be necessary for accounts.js to load utils.js.

Hope this helps

answered May 4, 2011 at 5:23

Edgar Villegas Alvarado

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2 Comments

Matty F Over a year ago

thanks @Edgar. I also read that nesting isnt required so you can have: $script('util.js', 'util'); $script('accounts.js', 'accounts'); $script.ready('accounts', function() { fnA });

Matty F Over a year ago

to avoid race conditions you also need to have inside accounts.js: $script.ready('util', function...);

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