Use variable as operator in if test

Question

I am trying to use a variable as an operator inside an if test.

if [[ $action = "active" ]];then operator="-le" fi if [[ $Apps $operator 100 ]];then echo "No of apps $Apps" fi

I am getting syntax error near `

Near what? Near `? There's no backtick in your code.

Enlico
– Enlico

2020-01-03 18:31:05 +00:00
Commented Jan 3, 2020 at 18:31 — Enlico
– Enlico, Commented Jan 3, 2020 at 18:31

chepner · Accepted Answer · 2020-01-03 18:32:43Z

You can switch to [, which won't seen its arguments until after the shell has expanded all the parameters. [[ has to be fully parsed before $operator is expanded, and it needs to see an actual operator.

if [ "$Apps" "$operator" 100 ]; then echo "No of apps $Apps" fi

Romeo Ninov · Accepted Answer · 2020-01-03 18:34:04Z

0

Have you try nested if operators?

if [ "$action" = "active" ] then if [ "$Apps" -eq 100 ] ....

answered Jan 3, 2020 at 18:34

Romeo Ninov

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1 Comment

Kris Over a year ago

Thanks for response .. Because of other code.. i have to do it seperately .. But single bracket worked

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