Im reading strings from a csv file. These strings contain "\n" chars to represent new lines. How can I print these strings with the correct new lines? Using str() didn't work.
CSV File has only one line:
Dest, Test\n Test2\n Test3 The code below prints Test\n Test2\n Test3
for ifile in files: with open(orderPath + '\\' + ifile) as csv_file: csv_reader = csv.reader(csv_file, delimiter=',') for row in csv_reader: dest = row[0] message = row[1] message = str(message) print(message) It's unclear precisely how you want the data in the csv file to be interpreted, but here's a guess. It uses the ast.literal_eval() function to convert the escape characters in the input data into newline characters.
This involves enclosing the second column in triple double-quotes (""") characters to allow it to interpreted as Python string literal. Triple quotes are used in case the enclosed text itself contains quotes. For example: Dest, Test\n "Test2"\n Test3
import ast import csv filename = 'one_line.csv' with open(filename, newline='') as csv_file: for row in csv.reader(csv_file, delimiter=','): dest = row[0] message = ast.literal_eval('"""{}"""'.format(row[1])) print(dest) print(message) Output:
Dest Test Test2 Test3 
If I understand correctly, you want to replace the sequence of literal characters '\' and 'n' in your input with newlines:
Instead of:
message = str(message) You want:
message = message.replace('\\n', '\n') 