Reading float values from a csv file in Scala?

Question

I want to send (integer) values from a csv file to a (Chisel) class here.

I just can't read the values from a csv file - I have already tried all code snippets scattered around the internet. (csv file is in the format below ->)

1321437196.0, -2132416838.0, 1345437196.0

Code I am using:

val bufferedSource = io.Source.fromFile("sourceFile.csv") val rows = Array.ofDim[Int](3) var count = 0 for (line <- bufferedSource.getLines) { rows(count) = line.split(",").map(_.trim).toString.toInt count += 1 } bufferedSource.close println(rows.mkString(" "))

Output:

[Ljava.lang.String;@51f9ef45 [Ljava.lang.String;@2f42c90a [Ljava.lang.String;@6d9bd75d

I have understood the error message and tried all various snippets mentioned here(Printing array in Scala , Scala - printing arrays) , but I just can't see where I am going wrong here. Just to point out, I don't want a Double value here but want a converted Signed Integer , hence that is why toInt.

Thanks will appreciate help with this!

split yields an array, you want split(comma)(0). You might consider something simple like "314.0,".stripSuffix(".0,").toInt. — som-snytt
– som-snytt, Commented Mar 2, 2020 at 1:27

jwvh · Accepted Answer · 2020-03-02 06:44:04Z

"1.0".toInt won't work. Need to go from String to Float to Int.

val bufferedSource = io.Source.fromFile("sourceFile.csv") val rows = bufferedSource.getLines .map(_.split(",").head.trim.toFloat.toInt) .toArray bufferedSource.close rows //res1: Array[Int] = Array(1321437184, -2132416896, 1345437184)

Suhas NM · Accepted Answer · 2020-03-02 06:21:29Z

1

Change

line.split(",").map(_.trim).toString.toInt

to

line.split(",")(0).trim.toInt

edited Mar 2, 2020 at 6:21

answered Mar 2, 2020 at 6:04

Suhas NM

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Comments

Dhirendra · Accepted Answer · 2020-03-02 07:22:05Z

val bufferedSource = io.Source.fromFile("sourceFile.csv") val rows = bufferedSource.getLines .map(_.split(",").headOption.mkString.toInt) bufferedSource.close

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