Why should I use StringTokenizer when I have split function? [duplicate]

Question

In my understanding the StringTokenizer divides the String in tokens which on printing produces same result as split function depending on the delimiter. For example, consider this code:

String str="This is a text."; StringTokenizer st=new StringTokenizer(str); while(st.hasMoreTokens()) { System.out.println(st.nextToken()); }

And this:

String str="This is a text."; String st[]=str.split(" "); for(int i=0;i<st.length;i++) { System.out.println(st[i]); }

In both the cases the output is:

This is a text.

Then why should I use StringTokenizer when I can achieve same thing with split function?

Easy. You shouldn't use StringTokenizer. Its Javadoc claims it is obsolete. — Dawood ibn Kareem
– Dawood ibn Kareem, Commented Mar 2, 2020 at 4:41
One advantage of StringTokenizer is that it will return which characters it splits on. String.split() doesn't, it just eats the delimiters. — markspace
– markspace, Commented Mar 2, 2020 at 4:52
@TestCase The documentation says: "StringTokenizer is a legacy class that is retained for compatibility reasons although its use is discouraged in new code. It is recommended that anyone seeking this functionality use the split method of String or the java.util.regex package instead". That means the class is obsolete, even if the word "obsolete" isn't explicitly used. — Slaw
– Slaw, Commented Mar 2, 2020 at 5:19

sprinter · Accepted Answer · 2020-03-02 04:41:11Z

Note the following in the documentation for StringTokenizer:

StringTokenizer is a legacy class that is retained for compatibility reasons although its use is discouraged in new code. It is recommended that anyone seeking this functionality use the split method of String or the java.util.regex package instead.

So the advice is: don't use it. It's there only to avoid breaking old code.

Test Case · Accepted Answer · 2020-03-02 05:49:11Z

Both does the same thing.

StringTokenizer is a legacy class that is retained for compatibility reasons. Its use is discouraged in new code. It is recommended to use the split method of String or the java.util.regex package instead.

From Java official docs.

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