jquery arrays comparison with substrings and case insensitive

Question

Folks I have a jquery function requirement that will compare two arrays.

listA = [' APPLE', 'banana', 'orange'] listB = [ 'BANANA ','appl']

ok so in above example, I need function to return "true". Basically what I need is a way to

Strip each word in both arrays to get rid of leading and trailing spaces.
Perform comparison which needs to be case insensitive.
Compare substring level, which means 'appl' does exist within ' APPLE', so it should be true

my code so far

<script> $(document).ready(function(){ Array.prototype.contains = function(array) { return array.every(function(item) { array = $.map(this, function(value){ return value.replace(/ /g, '').toUpperCase(); }); return array.indexOf(item.replace(/ /g, '').toUpperCase()) >= 0; }, this); } var result = [' APPLE', 'banana ', 'orange'].contains([ ' BANANA',' Appl ']); alert(result); });

so in above code example, it should return "true"

Any help is much appreciated

dee.ronin · Accepted Answer · 2020-04-15 01:38:51Z

You can update the Array.prototype.contains function as below, this will remove the leading and trailing spaces and use a case insensitive comparison under the map function:

Array.prototype.contains = function(array) { return array.every(function(item) { var searchResult = this.map(function(i) { return i.trim().toLowerCase().indexOf(item.trim().toLowerCase()) >= 0; }); return searchResult.includes(true); }, this); }

Sarma · Accepted Answer · 2020-04-15 01:08:35Z

Instead of return within array.every( .. )

use a counter. Then ..

return counter == array.length

Osiris · Accepted Answer · 2020-04-15 01:10:22Z

You can use toUpperCase() or toLowerCase() methods when doing the comparison.

for example:

let areEqual = str1.toUpperCase() === str2.toUpperCase();

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