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Trying to run simple python file in python prompt but giving an error:

content of test.py

print("Trying to print this using .py file on anaconda prompt")

Running file from python prompt

(base) C:\Users\acharbha>python Python 3.6.5 |Anaconda, Inc.| (default, Mar 29 2018, 13:32:41) [MSC v.1900 64 bit (AMD64)] on win32 Type "help", "copyright", "credits" or "license" for more information. >>> python C:\Users\acharbha\Documents\python\test.py File "<stdin>", line 1 python C:\Users\acharbha\Documents\python\test.py ^ SyntaxError: invalid syntax >>>
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    execfile('test.py') Commented Jul 6, 2020 at 16:10
  • 2
    You are trying to run a shell/cmd command inside of the python IDLE. Commented Jul 6, 2020 at 16:10
  • @jordanm Just curious, how can you tell it's IDLE? It looks like any other REPL to me. Commented Jul 6, 2020 at 16:22
  • You are trying to run a shell/cmd command inside of the python console. Commented Jul 6, 2020 at 16:33

2 Answers 2

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To execute in shell: python test.py

To execute inside the interpreter: exec(open("test.py").read())

This should help: How to execute a file within the python interpreter?

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You are trying to run it within the python interpreter. So just exit that and run the command on the terminal.

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