one-liner-return with 3 if-statements [duplicate]

Question

I have the following Code in Python:

def show_sequence(n): if n > 0: return "+".join((str(i) for i in range(n+1))) + " = %d" %(sum(range(n+1))) elif n == 0: return "0=0" else: return str(n) + "<0"

Question: Is there a syntax correct way of putting all lines into one return statement if there are 3 if-statements? I know it works with one if- & else-statement but im a fan of one-liner and already asked this myself several times.

Only if you wanted one absurdly long and hard to read line instead of code that makes sense. — khelwood
– khelwood, Commented Jul 9, 2020 at 18:45
I know, this is a bad example for clear coding but I could not figure out, how the syntax should look like. Already tried by using "or" but it did not work — Jero
– Jero, Commented Jul 9, 2020 at 18:47
return "+".join(...) if n > 0 else "0=0" if n == 0 else str(n) + "<0". (But if anyone else has to read your code, please don't inflict this kind of syntax abuse on them). — ekhumoro
– ekhumoro, Commented Jul 9, 2020 at 18:53
I wouldn't put everything on one line, but you also can easily generalize n > 0 and n == 0 into a single n >= 0 case, as "+".join([0]) == "0" and sum([0]) == 0. — chepner
– chepner, Commented Jul 9, 2020 at 19:00

Simon Crane · Accepted Answer · 2020-07-09 18:48:00Z

Inline if-statements can be chained like this:

"a" if 0 else "b" if 0 else "c"

(replace the 0s with 1s to see the return value change)

fro · Accepted Answer · 2020-07-09 18:49:59Z

0

You can use this:

result = True if a==b else False

answered Jul 9, 2020 at 18:49

fro

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