Bash: Formatting date [duplicate]

Question

I would like to use date in the following format: yyyyMM.dd.HHmm. i.e. 202008.15.1742

This is the Bash file:

#!/usr/bin/env bash VERSION_CODE=$((($(date +%s%N)/1000000)) plutil -replace CFBundleVersion -string "$VERSION_CODE"

How do I set VERSION_CODE such that the current time appears in this format: yyyyMM.dd.HHmm?

#VERSION_CODE=$(date +%Y%m.%d.%H%M) #echo $VERSION_CODE 202008.13.2155 — GaryB
– GaryB, Commented Aug 14, 2020 at 0:55

Léa Gris · Accepted Answer · 2020-08-14 06:58:57Z

5

A pure Bash solution without spawning a sub-process:

printf -v VERSION_CODE '%(%Y%m.%d.%H%M)T'

answered Aug 14, 2020 at 6:58

20.2k4 gold badges39 silver badges52 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

1218985 · Accepted Answer · 2020-08-14 00:52:53Z

2

You can do it like this:

VERSION_CODE=$(date +"%Y%m.%d.%H%M")

answered Aug 14, 2020 at 0:52

8,1122 gold badges29 silver badges33 bronze badges