I want to filter url's like bartender/profili/20/friends using preg_match.
Regex:
/^\/bartender\/profili\/d+\/friends/ Unfortunately it doesn't work.
Could somebody help?
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6 Answers
Do you want to capture the \d+? If so, enclose them in ( ), that should fix it. Also, if you're regex uses /, I'd suggest using a different delimiter, less escaping that way:
<?php preg_match( '~^/bartender/profili/(\d+)/friends~', '/bartender/profili/20/friends', $matches ); var_dump( $matches ); Addendum: and - like everyone already mentioned - you indeed forgot the \ in front of the d+, but that was easy to overlook if you have to escape every / ;)
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You have a slash in front of d+ (and have selected a badly readable delimiter for this situation). Try this:
#^\/bartender\/profili\/\d+\/friends#
you forgot to escape \d+
/^\/bartender\/profili\/\d+\/friends/ 
2 Comments
Berry Langerak
@genesis; no, he didn't, please read more carefully before a downvote. Upvoting the answer.
Karolis
@genesis, you are wrong. Look carefully. I have added an extra backslash before
d+You are missing a backslash before d+: \d+
answered Jun 17, 2011 at 11:12
Ferdinand Beyer
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"bartender\/profili\/[0-9]+\/friends" also works. Here's an excellent resource for trying regular expressions: http://www.regextester.com/
Comments
You do not have to escape forward slashes, but you need to escape meta-characters (like 'd' for decimal digits)
^/bartender/profili/\d+/friends/
1 Comment
Berry Langerak
If / is your delimiter you do have to escape the forward slashes. You ignored the delimiters altogether it seems.