Where can I edit the Copyright of my Python Bundle created with py2app?

I use py2app for the creation of stand alone apps from my python scripts. I have Tkinter used in the script called "MyApp" but I wonder where I can edit the copyright of my app? When I go to "About MyApp" from menu bar which was created by py2app, I see the Tkinter copyright.

So, what do I need to do to get my own name for my own app in py2app here?

Wishes, Mike

from tkinter import * from tkinter import messagebox root = Tk() root.wm_title("Calculate something") root.config(background="#FFFFFF") leftFrame = Frame(root, width=200, height=400) leftFrame.grid(row=0, column=0, padx=10, pady=3) leftLabel1 = Label(leftFrame, text="This app helps to calculate") leftLabel1.grid(row=0, column=0, padx=10, pady=3) rightFrame = Frame(root, width=200, height=400) rightFrame.grid(row=0, column=1, padx=10, pady=3) rightLabel1 = Label(rightFrame, text="1st number:") rightLabel1.grid(row=0, column=1, padx=10, pady=3) rightLabel2 = Label(rightFrame, text="2nd number") rightLabel2.grid(row=1, column=1, padx=10, pady=3) rightLabel3 = Label(rightFrame, text="you get") rightLabel3.grid(row=3, column=1, padx=10, pady=25) num1_var = DoubleVar() num2_var = DoubleVar() # entrys num1_ent = Entry(rightFrame, width=30, textvariable=num1_var) num1_ent.grid(row=0, column=2, padx=10, pady=3) num2_ent = Entry(rightFrame, width=30, textvariable=num2_var) num2_ent.grid(row=1, column=2, padx=10, pady=3) def calc(): num1 = num1_var.get() num2 = num2_var.get() if num1 == num2: messagebox.showerror(titel = "Error", message = "Different numbers are needed", icon = "error") elif num1 < num2: rightLabel4 = Label(rightFrame, width=30, text=((num2 - num1)-1)) rightLabel4.grid(row=3, column=2, padx=10, pady=25) elif num1 > num2: rightLabel4 = Label(rightFrame, width=30, text=((num2 - num1)-5)) rightLabel4.grid(row=3, column=2, padx=10, pady=25) buttonFrame = Frame(rightFrame) buttonFrame.grid(row=3, column=1, padx=10, pady=3) B1 = Button(rightFrame, text="Do it", bg="#FF0000", width=15, command=calc) B1.grid(row=2, column=2, padx=50, pady=10) root.mainloop()