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So I am having trouble with getting random item from random list inside a dictionary. The code I have right now

tasktotal = ["Medbay/Submit Scan","Medbay/Submit Example","Cafeteria/Connect Wire","Electrical/Connect Wire","Cafeteria/Empty Garbage","Security/Connect Wire","Navigation/Navigate","Upper Engine/Fuel","Lower Engine/Fuel","Shield/Prime Shield","Storage/Empty Garbage","Admin/Swipe Card","Weapon/Clear Asteroid","Admin/Connect Wire","Storage/Connect Wire"]

And then I did

task = dict(s.split('/') for s in task)

The problem with this is that I can only have one task in one location. I want to make it list in dictionary and also pick a random task from random location.

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    The code you've shown is just a list. To choose a random item from a list, use random.choice(my_list). We can't answer your question about dictionaries, because you haven't shown us an example. Commented Oct 31, 2020 at 21:55
  • That produces a dictionary of simple string pairs, none of which is a list. So again, we can't answer the question, because we don't have an example to work with. Commented Oct 31, 2020 at 22:02

4 Answers 4

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You can make a dictionary that maps keys to lists like this (alternatively you can use a defaultDict):

tasktotal = ["Medbay/Submit Scan","Medbay/Submit Example","Cafeteria/Connect Wire","Electrical/Connect Wire","Cafeteria/Empty Garbage","Security/Connect Wire","Navigation/Navigate","Upper Engine/Fuel","Lower Engine/Fuel","Shield/Prime Shield","Storage/Empty Garbage","Admin/Swipe Card","Weapon/Clear Asteroid","Admin/Connect Wire","Storage/Connect Wire"] d = {} for k, v in (s.split('/') for s in tasktotal): d.setdefault(k, []).append(v)

this will make d look like:

{'Medbay': ['Submit Scan', 'Submit Example'], 'Cafeteria': ['Connect Wire', 'Empty Garbage'], 'Electrical': ['Connect Wire'], 'Security': ['Connect Wire'], 'Navigation': ['Navigate'], 'Upper Engine': ['Fuel'], 'Lower Engine': ['Fuel'], 'Shield': ['Prime Shield'], 'Storage': ['Empty Garbage', 'Connect Wire'], 'Admin': ['Swipe Card', 'Connect Wire'], 'Weapon': ['Clear Asteroid']}

Given that you can get a random value from any list you like:

import random random.choice(d['Medbay']) # 'Submit Example' (or 'Submit Scan')
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Thanks, this is really useful
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First you need to create a dictionary. Keys are unique, if you want to store multiple values under one key, store a list as value. Then draw from it:

tasktotal = ["Medbay/Submit Scan","Medbay/Submit Example","Cafeteria/Connect Wire", "Electrical/Connect Wire","Cafeteria/Empty Garbage", "Security/Connect Wire","Navigation/Navigate", "Upper Engine/Fuel","Lower Engine/Fuel","Shield/Prime Shield", "Storage/Empty Garbage","Admin/Swipe Card","Weapon/Clear Asteroid", "Admin/Connect Wire","Storage/Connect Wire"] # import defaultdict # d = defaultdict(list) # instead of d={} and then simply use d[key].append(...) it creates # the list itself data = {} for task in tasktotal: key, value = task.split("/") # either use plain dict and test key yourself if key in data: data[key].append(value) else: data[key] = [value] # or use setdefault # d.setdefault(key,[]).append(value) # or # d[key].append(...) with defaultdict(list) print(data)

Then query randomly:

import random # random key/value-list pair key,values = random.choice(list(data.items())) # random item from value-list print(key, "->", random.choice(values))

Output:

'edbay': ['Submit Scan', 'Submit Example'], 'Cafeteria': ['Connect Wire', 'Empty Garbage'], 'Electrical': ['Connect Wire'], 'Security': ['Connect Wire'], 'Navigation': ['Navigate'], 'Upper Engine': ['Fuel'], 'Lower Engine': ['Fuel'], 'Shield': ['Prime Shield'], 'Storage': ['Empty Garbage', 'Connect Wire'], 'Admin': ['Swipe Card', 'Connect Wire'], 'Weapon': ['Clear Asteroid']} Lower Engine -> Fuel

You could have combined answers to these 2 questions to selfanswer yours:

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You could use itertools.groupby

Note that the iterable you feed to groupby should be sorted on the same key you use for grouping, but in your case that is a simple sort…

In [12]: from itertools import groupby ...: data = ["Medbay/Submit Scan","Medbay/Submit Example","Cafeteria/Connect Wire","Electrical/Connect Wire","Cafeteria/Empty Garbage","Security/Connect Wire","Navigation/Navigate","Upper Engine/Fuel","Lower Engine/Fuel","Shield/Prime Shield","Storage/Empty Garbage","Admin/Swipe Card","Weapon/Clear Asteroid","Admin/Connect Wire","Storage/Connect Wire"] ...: data.sort() ...: {k:list(s[1] for s in g) ...: for k, g in groupby((s.split('/') for s in data), lambda s:s[0])} Out[12]: {'Admin': ['Connect Wire', 'Swipe Card'], 'Cafeteria': ['Connect Wire', 'Empty Garbage'], 'Electrical': ['Connect Wire'], 'Lower Engine': ['Fuel'], 'Medbay': ['Submit Example', 'Submit Scan'], 'Navigation': ['Navigate'], 'Security': ['Connect Wire'], 'Shield': ['Prime Shield'], 'Storage': ['Connect Wire', 'Empty Garbage'], 'Upper Engine': ['Fuel'], 'Weapon': ['Clear Asteroid']} In [13]: d = _ In [14]: from random import choice In [15]: rk = choice(list(d.keys())) In [16]: rk Out[16]: 'Lower Engine' In [17]: choice(d[rk]) Out[17]: 'Fuel'

In its way, elegant…

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convert your code to dic to get value by key tasktotal = ["Medbay/Submit Scan","Medbay/Submit Example","Cafeteria/Connect Wire","Electrical/Connect Wire","Cafeteria/Empty Garbage", "Security/Connect Wire","Navigation/Navigate","Upper Engine/Fuel","Lower Engine/Fuel","Shield/Prime Shield", "Storage/Empty Garbage","Admin/Swipe Card","Weapon/Clear Asteroid","Admin/Connect Wire","Storage/Connect Wire"] dic = {} key = 0 for i in tasktotal: i = i.split('/') dic[key] = i[0] key+=1 dic[key] = i[1] key+=1 print(dic)
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