Trying to create program that exits after 6 incorrect attempts at entering username and password

Question

In the beginning stages of learning Python and I've hit a bit of a snag

I'm trying to create a program that asks for a specific username and password. After 6 incorrect attempts, it will quit the program. Sample code works fine when I put in the correct info. The issue I'm having is when the username is correct but the password is not. I want it to print that the "password doesn't match" and re-ask for the password. It takes me back to the beginning of the program and asks for my username again. Any ideas to solve this? Thank you in advance!

Code can also be found here: https://pastebin.com/4wSgB0we

import sys incorrect = 0 max_tries = 6 choices = ['Drake', 'swordfish'] run = True while run: while incorrect < max_tries: user_input = input('Please enter username: ') if user_input not in choices: incorrect += 1 print(f"{user_input} is incorrect. Please try again.") else: print(f"Welcome back {user_input}.") pass_input = input('Please enter password: ') if pass_input not in choices: incorrect += 1 print("Password does not match. Please try again") else: run = False print('Access granted') sys.exit() if incorrect == max_tries: sys.exit()

Add another while loop under the else?

Tomerikoo
– Tomerikoo

2020-12-17 08:34:26 +00:00
Commented Dec 17, 2020 at 8:34 — Tomerikoo
– Tomerikoo, Commented Dec 17, 2020 at 8:34

dudulu · Accepted Answer · 2020-12-17 08:08:10Z

If it didn't help you solve the problem.
I will modify.

When your user is correct, you should leave While.
If you do not leave While, the user account will be asked again.

while run: while incorrect < max_tries: user_input = input('Please enter username: ') if user_input not in choices: incorrect += 1 print(f"{user_input} is incorrect. Please try again.") else: print(f"Welcome back {user_input}.") break while incorrect < max_tries: pass_input = input('Please enter password: ') if pass_input not in choices: incorrect += 1 print("Password does not match. Please try again") else: run = False print('Access granted') sys.exit() if incorrect == max_tries: sys.exit()

You should add a reason for your modification – this way, @gyalchestor, might learn what he did wrong in the first place.
Sorry, my English is not good and I rely on google translation, so I can't explain it well.

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