Bind interactive command to a key sequence

Question

I'm facing an interesting problem while compiling and executing a C program involving scanf(). I'm using Ubuntu 20.04 LTS with Bash and GCC v10.2.0.

#include <stdio.h> int main(void) { int decimalInteger; printf("Enter a decimal integer value: "); scanf("%d", &decimalInteger); printf("It can also be written in octal and hexadecimal notations as %o and %x, respectively.\nWith C prefixes, they are %#o (for octal) and %#x/%#X (for hexadecimal).\n", decimalInteger, decimalInteger, decimalInteger, decimalInteger, decimalInteger); return 0; }

When I compile and run this with gcc-10 *.c -std=c11 && ./a.out, it works perfectly fine. Upon pressing the enter key after the input, the cursor moves to the next line.

Output using full command:

But, when I add bind -x '"\C-h":gcc-10 *.c -std=c11 && ./a.out' to .bashrc and then use Ctrl+H to compile & execute the program, the output looks like this:
this

The console doesn't display the input, and the cursor doesn't move to the next line.

Why is this happening?

oguz ismail · Accepted Answer · 2021-05-25 18:27:03Z

This is normal, readline changes terminal settings while reading input. Line editing wouldn't be possible otherwise.

You need to save original terminal settings into a variable, and restore them before running your program.

stty_orig=$(stty -g) my_func() { local stty_bkup=$(stty -g) stty "$stty_orig" # compile and run here stty "$stty_bkup" } bind -x '"\C-h": my_func'

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