Say I have a list that looks like this
f = [['person','place','item'],['george','home','phone']] how would I search through that list and delete a specific cell using f.remove() I have tried:
f.remove('item') which should remove 'item' but instead it returns the error
Exception has occurred: ValueError list.remove(x): x not in list you have list of lists, if you want to remove item from 1st list, you should do the following way:
f[0].remove('item') .remove() is inplace operation and doesn't return any value. i.e it will change the list itself, so after above operation your list will be:
print(f) # output [['person', 'place'], ['george', 'home', 'phone']] for second list:
f[1].remove('home') 
You can use list comprehension to do this. You need to put the if statement inside the inner loop.
f = [['person','place','item'],['george','home','phone']] f = [[a for a in x if a != 'item'] for x in f] The output of this will be:
[['person', 'place'], ['george', 'home', 'phone']] This is equivalent to:
f = [['person','place','item'],['george','home','phone']] new_f = [] for x in f: temp_list = [] for a in x: if a != 'item': temp_list.append(a) new_f.append(temp_list) print (new_f) The output of both will be the same.
item with apple, it will print the full list as apple is not in the list. With list.remove('apple'), you need to solve for ValueErrorHave you tried this?
f[0].remove('item') You can do it easily using list comprehension
f=[x.remove('item') if 'item' in x else x for x in f] 
itemIn your example f is a two-dimensional list, so all the items in f are also lists, and item is not one of them. Depending on your use case, I can see multiple ways of interpreting "remove":
If you want your resulting list to be [['person','place'],['george','home','phone']], you can use
f[0].remove('item') If you want your resulting list to be [['person','place'],['george','home']] (i.e. removing the whole "column" from the 2D list), then you should first find the index you want to remove, and then use del based on the index:
index = f[0].index('item') for row in f: del row[index] 
f[0].remove('item')csv.DictWriterthat writes a list of dicts to a CSV file.None.