How to create a continuously running socket client in python

Question

I have been using TCP socket for a while now in python and my socket client closes after sending a message but I want to create a continuously running socket client that will keep sending messages as I already have a continuously running listener server. So the socket client code which I like to work on is below:

import socket TCP_IP = "0.0.0.0" TCP_PORT = 5003 BUFFER_SIZE = 1024 array = [0, 5, 10, 15] print("Sending sensor value",array) MESSAGE = bytearray(array) # converting to bytearray for sending via socket # Sending via socket s = socket.socket(socket.AF_INET,socket.SOCK_STREAM) s.connect((TCP_IP,TCP_PORT)) s.send(MESSAGE) data = s.recv(BUFFER_SIZE) s.close()

please advise

Did you see the examples at the end of the socket documentation?? — wwii
– wwii, Commented Jan 16, 2021 at 16:02
There are quite a few questions and answers on SO searching with your question. Do any of them answer your question? If so, let us know and we will mark yours as a duplicate. — wwii
– wwii, Commented Jan 16, 2021 at 16:07
@mkrieger1 yes I did. it workes but after some time my Linux freezes. That is why I was looking for all possible ways. — Farhan Kabir
– Farhan Kabir, Commented Jan 16, 2021 at 16:14

Winters · Accepted Answer · 2021-01-16 16:21:23Z

Try this:

import socket import time TCP_IP = "0.0.0.0" TCP_PORT = 5003 BUFFER_SIZE = 1024 array = [0, 5, 10, 15] MESSAGE = bytearray(array) # converting to bytearray for sending via socket # Sending via socket while True: s = socket.socket(socket.AF_INET,socket.SOCK_STREAM) s.connect((TCP_IP,TCP_PORT)) s.send(MESSAGE) data = s.recv(BUFFER_SIZE) print("Sending sensor value",array) time.sleep(3) s.close()

Thanks a lot! Actually, I tried it just now and it is working. Didn't put any delay though before

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