How to extract seconds from datetime.timedelta

Question

I have a list of dates and hours. For each date, I would like to extract only the seconds value.

Here is my script :

import datetime format_string = "%Y-%m-%d %H:%M" now = datetime.datetime.now() date = ['2021-01-29 15:15', '2021-01-29 15:50', '2021-01-29 17:00'] date = [(datetime.datetime.strptime(i, format_string)-now) for i in date] print(date)

And here is the output :

[datetime.timedelta(seconds=7269, microseconds=211221), datetime.timedelta(seconds=9369, microseconds=211221), datetime.timedelta(seconds=13569, microseconds=211221)]

I just want the seconds for the three elements of the list 'data'

Eduardo Coltri · Accepted Answer · 2021-01-29 12:20:41Z

Just change

date = [(datetime.datetime.strptime(i, format_string)-now) for i in date]

To

date = [(datetime.datetime.strptime(i, format_string)-now).seconds for i in date]date = [(datetime.datetime.strptime(i, format_string)-now) for i in date]

I am glad to help! You can also use ´total_seconds`, as its shown here

ahmedaao · Accepted Answer · 2021-01-29 12:24:11Z

It works with :

date = [(datetime.datetime.strptime(i, format_string)-now).seconds for i in date]

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