I'm making a simple calculator program for a class project. I have an Exception handler that catches errors and returns the error type. Though whenever it catches an Exception, it prints the error type along with its description. Is there a way to only have it print the error type?
Code:
operations = ('Add', 'Subtract', 'Multiply', 'Divide') def insigStrip(flt): if str(flt)[-1] == '0': return int(flt) return flt def main(): print('Select operation:') for i in range(len(operations)): print(str(i+1) + ':', operations[i]) while True: try: option = int(input('Enter choice(1/2/3/4): ')) if option in range(len(operations) + 1): x = insigStrip(float(input('Enter first number: '))) n = insigStrip(float(input('Enter second number: '))) if option == 1: print(x, '+', n, '=', insigStrip(x+n)) if option == 2: print(x, '-', n, '=', insigStrip(x-n)) if option == 3: print(x, '*', n, '=', insigStrip(x*n)) if option == 4: try: print(x, '/', n, '=', insigStrip(x/n)) except ZeroDivisionError: print('Cannot divide by Zero.') break else: print('Invalid input.') continue except Exception as e: print('Error caught:', repr(e)) if __name__ == '__main__': main() For x or n, it only accepts 1, 2, 3, or 4 as input. Say for example, I were to input t for x. This would raise a ValueError. The try except statement inside the while loop then catches said ValueError and prints out Error caught: type(error).
Desired Output:
>>> t Error caught: ValueError Given output:
>>> t Error caught: <class 'ValueError'> (if type(e)) or:
>>> t Error caught: ValueError: insert error description (if repr(e)) How do I get the desired output?
