q = [] num = ["1","2","3","4","5","6","7","8","9","0"] while True: dat = float(input("Enter Name: ")) if dat == "*": print(q.pop(0)) if dat in num : break else: q.append(dat) #the program only terminates when inputted 0 to 9 numbers but I want it to terminate if any numbers are inputted.
Use .isdigit(). Try in this way-
q = [] #num = ["1","2","3","4","5","6","7","8","9","0"] while True: dat = input("Enter Name: ") if dat == "*": print(q.pop(0)) if dat.isdigit() : break else: q.append(dat) Instead of checking if dat is a digit, should then check if any of its characters is a digit:
q = [] somedigit = False while True: dat = input("Enter Name: ") if dat == "*": print(q.pop(0)) for element in dat: if element.isdigit(): somedigit = True break if somedigit == True: break else: q.append(dat) Other way is to check the function isalpha:
q = [] while True: dat = input("Enter Name: ") if dat == "*": print(q.pop(0)) if not dat.isalpha(): break else: q.append(dat) 