How to copy all the attributes of one element and apply them to another?

ES6 syntax one liner:

function cloneAttributes(target, source) { [...source.attributes].forEach( attr => { target.setAttribute(attr.nodeName ,attr.nodeValue) }) } 

And as noted in the first comment - you would probably don't want to copy the source id attribute... so this one will save it as a 'data-id' attribute in case you need a reference.

function cloneAttributes(target, source) { [...source.attributes].forEach( attr => { target.setAttribute(attr.nodeName === "id" ? 'data-id' : attr.nodeName ,attr.nodeValue) }) } 

Pretty Simple

function cloneAttributes(element, sourceNode) { let attr; let attributes = Array.prototype.slice.call(sourceNode.attributes); while(attr = attributes.pop()) { element.setAttribute(attr.nodeName, attr.nodeValue); } } 

A working solution on jsfiddle

EDIT

Updated jsfiddler

Javascript

$(function(){ var destination = $('#adiv').eq(0); var source = $('#bdiv')[0]; for (i = 0; i < source.attributes.length; i++) { var a = source.attributes[i]; destination.attr(a.name, a.value); } }); 

HTML

<div id="adiv" class="aclass">A class</div> <div id="bdiv" class="bclass">B class</div> 

That's copying #bdiv attributes to #adiv.

We could also try extending the jQuery prototype ($.fn) object to provide a new method that can be chained to the jQuery() function.

Here's an extension of @pimvdb's solution to provide a function that copies all attributes

The usage would be like so:

 $(destinationElement).copyAllAttributes(sourceElement); 

The extension function can be defined like so:

(function ($) { // Define the function here $.fn.copyAllAttributes = function(sourceElement) { // 'that' contains a pointer to the destination element var that = this; // Place holder for all attributes var allAttributes = ($(sourceElement) && $(sourceElement).length > 0) ? $(sourceElement).prop("attributes") : null; // Iterate through attributes and add if (allAttributes && $(that) && $(that).length == 1) { $.each(allAttributes, function() { // Ensure that class names are not copied but rather added if (this.name == "class") { $(that).addClass(this.value); } else { that.attr(this.name, this.value); } }); } return that; }; })(jQuery); 

An Example is available at http://jsfiddle.net/roeburg/Z8x8x/

Hope this helps.

You can try this:

function copyAttributes(from, to) { $($(from)[0].attributes). each(function(){$(to).attr(this.nodeName, this.nodeValue);}); return $(to); }; 

The return statement lets you write things like:

copyAttributes(some_element, $('<div></div>')).append(...) ... 

Hope this helps.

A non-jquery solution:

function copy(element){ var clone = document.createElement(element.nodeName); for(key in element){ clone.setAttribute(key,element[key]); } return clone; } 

It copies methods and other stuff you probably don't need, but hopefully you don't mind. This code is small and simple.

I'm facing same problem and after invested lots of time and effort i am creating thisclone textarea into editable div with same attribute

select.getAttributeNames().forEach(attrName => { $(div).attr(attrName, inputData.getAttribute(attrName)); }); 

A very straight to the point solution would be make something like this:

const _$ = domQuery => document.querySelector(domQuery) let div1 = _$('#div-1') let div2 = _$('#div-2') for(attr of div1.attributes) { div2.setAttribute(attr.name, attr.value); }

.my-div { height: 100px; width: 100px; }

<h1>div-1</h1> <div atribute-test="test" class="my-div" style="background: red" id="div-1"></div> <h1>div-2</h1> <div id="div-2"></div>

Since Firefox 22, Node.attributes is no longer supported (not implemented by other browsers and removed from the spec). It is only supported on Element (Element.attributes).

Javascript solution

Copy the attributes of old element to the new element

const $oldElem = document.querySelector('.old') const $newElem = document.createElement('div') Array.from($oldElem.attributes).map(a => { $newElem.setAttribute(a.name, a.value) }) 

Replace the old element with the new element, if required

$oldElem.parentNode.replaceChild($newElem, $oldElem) 

$("div").addClass($('#foo').attr('class'));