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dict_1 = { (40, 615): {1: ["03/02/2013"]}, (40, 558): {1: ["03/20/2013"]}, (40, 501): {1: ["04/03/2013"]}, (40, 342): {1: ["04/04/2013"]}, (40, 248): {1: ["04/08/2013"]}, (40, 88): {1: ["04/12/2013"]}, (40, 584): {8: ["06/21/2013"]}, (40, 480): {2: ["04/12/2013"]}, (40, 321): {2: ["04/12/2013"]}, (40, 121): {2: ["04/13/2013"]}, (40, 563): {3: ["04/15/2013"]}, (40, 404): {3: ["04/24/2013"]}, (40, 245): {3: ["04/26/2013"]}, (40, 141): {3: ["04/26/2013"]}, (40, 578): {4: ["04/29/2013"]}, (40, 474): {4: ["04/30/2013"]}, (40, 370): {4: ["04/30/2013"]}, (40, 201): {7: ["06/20/2013"]}, (64, 643): {5: ["05/03/2013"]}, (40, 484): {5: ["05/08/2013"]}, (40, 287): {5: ["05/31/2013"]}, (40, 171): {5: ["05/31/2013"]}, (40, 660): {6: ["06/03/2013"]}, (40, 544): {6: ["06/04/2013"]}, (40, 440): {6: ["06/12/2013"]}, (40, 281): {6: ["06/12/2013"]}, (40, 177): {6: ["06/12/2013"]}, (40, 619): {7: ["06/13/2013"]}, (40, 515): {7: ["06/14/2013"]}, (40, 411): {7: ["06/18/2013"]}, (40, 295): {7: ["06/19/2013"]}, (40, 97): {7: ["06/21/2013"]}, }

I want to sort this dictionary on nested keys.

Here is what I tried

def sort_dictionary(*new_dict): for unpack in new_dict: for key, value in sorted(unpack .items()): return key,':',value res = sorted(dict_1 .items(), key = lambda x: sort_dictionary(x[1]))

Of course, it is not giving me what I am expecting, please tell me if there is an easier way?

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    What is your expected output? Commented Jun 21, 2021 at 2:28

2 Answers 2

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Try it online!

def sort_dict(d): return dict(sorted(d.items(), key = lambda x: tuple(x[1].keys())[0])) dict_1 = { (40, 615): {1: ["03/02/2013"]}, (40, 558): {1: ["03/20/2013"]}, (40, 501): {1: ["04/03/2013"]}, (40, 342): {1: ["04/04/2013"]}, (40, 248): {1: ["04/08/2013"]}, (40, 88): {1: ["04/12/2013"]}, (40, 584): {8: ["06/21/2013"]}, (40, 480): {2: ["04/12/2013"]}, (40, 321): {2: ["04/12/2013"]}, (40, 121): {2: ["04/13/2013"]}, (40, 563): {3: ["04/15/2013"]}, (40, 404): {3: ["04/24/2013"]}, (40, 245): {3: ["04/26/2013"]}, (40, 141): {3: ["04/26/2013"]}, (40, 578): {4: ["04/29/2013"]}, (40, 474): {4: ["04/30/2013"]}, (40, 370): {4: ["04/30/2013"]}, (40, 201): {7: ["06/20/2013"]}, (64, 643): {5: ["05/03/2013"]}, (40, 484): {5: ["05/08/2013"]}, (40, 287): {5: ["05/31/2013"]}, (40, 171): {5: ["05/31/2013"]}, (40, 660): {6: ["06/03/2013"]}, (40, 544): {6: ["06/04/2013"]}, (40, 440): {6: ["06/12/2013"]}, (40, 281): {6: ["06/12/2013"]}, (40, 177): {6: ["06/12/2013"]}, (40, 619): {7: ["06/13/2013"]}, (40, 515): {7: ["06/14/2013"]}, (40, 411): {7: ["06/18/2013"]}, (40, 295): {7: ["06/19/2013"]}, (40, 97): {7: ["06/21/2013"]}, } print(sort_dict(dict_1))

Output:

{ (40, 615): {1: ["03/02/2013"]}, (40, 558): {1: ["03/20/2013"]}, (40, 501): {1: ["04/03/2013"]}, (40, 342): {1: ["04/04/2013"]}, (40, 248): {1: ["04/08/2013"]}, (40, 88): {1: ["04/12/2013"]}, (40, 480): {2: ["04/12/2013"]}, (40, 321): {2: ["04/12/2013"]}, (40, 121): {2: ["04/13/2013"]}, (40, 563): {3: ["04/15/2013"]}, (40, 404): {3: ["04/24/2013"]}, (40, 245): {3: ["04/26/2013"]}, (40, 141): {3: ["04/26/2013"]}, (40, 578): {4: ["04/29/2013"]}, (40, 474): {4: ["04/30/2013"]}, (40, 370): {4: ["04/30/2013"]}, (64, 643): {5: ["05/03/2013"]}, (40, 484): {5: ["05/08/2013"]}, (40, 287): {5: ["05/31/2013"]}, (40, 171): {5: ["05/31/2013"]}, (40, 660): {6: ["06/03/2013"]}, (40, 544): {6: ["06/04/2013"]}, (40, 440): {6: ["06/12/2013"]}, (40, 281): {6: ["06/12/2013"]}, (40, 177): {6: ["06/12/2013"]}, (40, 201): {7: ["06/20/2013"]}, (40, 619): {7: ["06/13/2013"]}, (40, 515): {7: ["06/14/2013"]}, (40, 411): {7: ["06/18/2013"]}, (40, 295): {7: ["06/19/2013"]}, (40, 97): {7: ["06/21/2013"]}, (40, 584): {8: ["06/21/2013"]}, }
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3 Comments

Thank you Arty! Here the output that you got is a list of tuples could you make it a nested dictionary. My expected output was like this { (40, 615): {1: ["03/02/2013"]}, (40, 558): {1: ["03/20/2013"]}, ...... (40, 584): {8: ["06/21/2013"]}, }
@ton.coder Done! See my updated answer. Now it is a dictionary on output.
@ton.coder To convert any list X of tuples to dictionary you just do X = dict(X).
0 
def sort_dict(d): return sorted(d.items(), key = lambda x: tuple(x[1].keys())[0]) sorted_dictionary = sort_dict(dict_1)

This code works great! But then I had to write some extra lines of code to convert sorted_dictionary from a list of tuples to a nested dictionary.

new_dict = {} for item in sorted_dictionary : new_dict[item[0]] = item[1] print(new_dict) {(40, 615): {1: ['03/02/2013']}, (40, 558): {1: ['03/20/2013']}, (40, 501): {1: ['04/03/2013']}, (40, 342): {1: ['04/04/2013']}, (40, 248): {1: ['04/08/2013']}, (40, 88): {1: ['04/12/2013']}, (40, 480): {2: ['04/12/2013']}, (40, 321): {2: ['04/12/2013']}, (40, 121): {2: ['04/13/2013']}, (40, 563): {3: ['04/15/2013']}, (40, 404): {3: ['04/24/2013']}, (40, 245): {3: ['04/26/2013']}, (40, 141): {3: ['04/26/2013']}, (40, 578): {4: ['04/29/2013']}, (40, 474): {4: ['04/30/2013']}, (40, 370): {4: ['04/30/2013']}, (64, 643): {5: ['05/03/2013']}, (40, 484): {5: ['05/08/2013']}, (40, 287): {5: ['05/31/2013']}, (40, 171): {5: ['05/31/2013']}, (40, 660): {6: ['06/03/2013']}, (40, 544): {6: ['06/04/2013']}, (40, 440): {6: ['06/12/2013']}, (40, 281): {6: ['06/12/2013']}, (40, 177): {6: ['06/12/2013']}, (40, 201): {7: ['06/20/2013']}, (40, 619): {7: ['06/13/2013']}, (40, 515): {7: ['06/14/2013']}, (40, 411): {7: ['06/18/2013']}, (40, 295): {7: ['06/19/2013']}, (40, 97): {7: ['06/21/2013']}, (40, 584): {8: ['06/21/2013']}}

Is there a better way without the extra lines of code?

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1 Comment

Yes, there is very easy way to convert list X of tuples to dictionary, just do X = dict(X), very simple. I updated my answer to reflect this change.

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