simplify complex logical condition in python

Question

How can I simplify this complex logical condition?

For a much shorter and more readable code

if i < 13: linux0[j] = query_res elif 13 <= i < 27: linux1[j] = query_res elif 27 <= i < 28: linux2[j] = query_res elif 28 <= i < 33: linuxDnsServer1[j] = query_res elif 33 <= i < 41: linuxRadius[j] = query_res elif 41 <= i < 46: gen[j] = query_res elif 46 <= i < 49: cdu[j] = query_res elif 49 <= i < 55: avalanche[j] = query_res elif 55 <= i < 69: defensePro_devices[j] = query_res

Barmar · Accepted Answer · 2021-08-04 19:50:24Z

4

It's not clear that it's more understandable, but you can put the limits and lists in another list, and iterate over it;

targets = [(12, linux0), (26, linux1), (27, linux2), (32, linuxDnsServer1), (40, linuxRadius), (45, gen), (48, cdu), (54, avalanche), (68, defensePro_devices)] for limit, target in targets: if i <= limit: target[j] = query_res break

answered Aug 4, 2021 at 19:50

Barmar

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3 Comments

Brian61354270 Over a year ago

To add: 1) If you need non-consecutive intervals, you can swap the limits with explicit range objects and then use if i in interval in place of if i <= limit. 2) You can also add an else branch at the end of the for to handle the case where no match is found (i.e. when the break statement is never reached)

Barmar Over a year ago

I was going to put #2 in, but since the original code doesn't print an error, I left it out.

Barmar Over a year ago

Another way to handle non-consecutive intervals is to use an extra list for the gaps.

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