How to pass optional parameter that comes after another optional parameter that you don't wish to specify

Question

I want to pass a parameter to override a deafult parameter that comes later in the function declaration than another default parameter that I want to let be default. Is this possible? Here's an example of what I want to do:

function f(a:string, b:number=1, c:string='FOO'){ // do stuff } f('val for a', 'val for c') // want b to still be default of 1

Please accept answers to your questions that you found to be satisfactory by clicking the checkmark outline next to them. — brunnerh
– brunnerh, Commented Oct 9, 2024 at 22:02

brunnerh · Accepted Answer · 2021-08-20 16:01:28Z

5

According to documentation you need to explicitly set b to undefined to get the default.

function test(a = 1, b = 2, c = 3) { console.log(a, b, c); } test(undefined, 42, undefined);

answered Aug 20, 2021 at 16:01

brunnerh

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1 Comment

bvandercar Over a year ago

sounds like it cannot be done and that I have to do this. Thanks. Solved

Awais · Accepted Answer · 2021-08-20 16:10:59Z

You can use undefined to get the default working. Here's the way you can accomplish this thing in a good stylistic way

function test(a:string, b:number=1, c:string='FOO') { //other stuff } let _ = undefined test('val for a', _, 'val for c');

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