I'm trying to use mkdir command in a bash script using a "*" wildcard. Full code is: mkdir -p $EXTRACTDIR/$CV_NAME*/release
It supposed to create a folder "release" in an existing "OpenCV-2.2.0" folder. Two computers does exactly that and the third creates a folder OpenCV*/release, and I can't figure out why.
Thnx for your help
The find command is a very useful command indeed, especially when using the -exec option. I whole heartedly recommend reading up on it further.
find ./$EXTRACTDIR -type d -name $CV_NAME\* -exec mkdir {}/release \; {} translates the result of the search into the mkdir comand. the parents option for mkdir ( -p ) is not needed because the folder must exist in order to be found.
On the third computer "OpenCV-2.2.0/release" doesn't exist, so wildcard matching will fail and will result in a string where * is untouched.
cd $EXTRACTDIR/$CV_NAME*; mkdir release
or
mkdir `echo $EXTRACTDIR/$CV_NAME*`/release if you have multiple $CV_NAME* directories, you have to use a loop.
