Print the middle integer from a list of sorted numbers

Question

Given a sorted list of integers, output the middle integer. Assume the number of integers is always odd

Input: 2 3 4 8 11

Output: 4

This is what I have so far

inputs=[] num_inputs=int(input()) if(num_inputs>9): print("Too many inputs") else: print(num_inputs) for i in range(num_inputs): inputs.append(input()) print(inputs) middle_position=int(num_inputs/2) print(inputs[middle_position])

OneCricketeer · Accepted Answer · 2021-10-19 21:59:36Z

Your input is only one line of data.

To read that into a list, you would use

inputs = list(map(int, input().split()))

Or just inputs = input.split() since you don't need ints

Then you would just need to check len(inputs) > 9 and get inputs[len(inputs) // 2]. No loops

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